Question
CSATEasyPrelims 2014Maths

Location of B is north of A and location of C is east of A. The distances AB and AC are 55 km and 1212 km respectively. The shortest distance (in km) between the locations B and C is

Explanation

A is at a reference point. B is 5 km north of A. C is 12 km east of A.

Using the Pythagorean theorem:

BC2=AB2+AC2BC^2 = AB^2 + AC^2

Substituting the values:

BC2=52+122BC^2 = 5^2 + 12^2

BC2=25+144BC^2 = 25 + 144

BC2=169BC^2 = 169

BC=169BC = \sqrt{169}

BC=13BC = 13 km

Therefore, the shortest distance between B and C is 13 km.

Maths PYQs from 2014

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