Option A is incorrect: To calculate the percentage growth in population from 1992 to 1993: $[\frac{21-20}{20}] \times 100 = (\frac{1}{20}) \times 100 = 5\%$ Since the population increases by 1 lakh every year, the percentage growth will decline as the base (total population) increases. For 1993-1994: $\frac{1}{21}$ For 1994-1995: $\frac{1}{22}$ With a constant numerator and a growing denominator, the fraction's value decreases each year, meaning the percentage growth will always be lower than 5% going forward.

Option B is incorrect: To calculate the income growth from 1992 to 1993: $[\frac{1111-1010}{1010}] \times 100 = (\frac{101}{1010}) \times 100 = 10\%$ To calculate the income growth from 1993 to 1994: $[\frac{1225-1111}{1111}] \times 100 = (\frac{114}{1111}) \times 100 = 10.2\%$ To calculate the income growth from 1994 to 1995: $[\frac{1245-1225}{1225}] \times 100 = (\frac{120}{1225}) \times 100 = 9.7\%$

Option C is correct: To calculate the per capita income in 1992: $\frac{1010}{20} = 5050$ To calculate the per capita income in 1993: $\frac{1111}{21} = 5290$ To calculate the per capita income in 1994: $\frac{1225}{22} = 5568$ To calculate the per capita income in 1995: $\frac{1345}{23} = 5847$

Option D is incorrect: By calculation above, we know per capita income was highest in 1995.