Question
CSATEasyPrelims 2025Maths

What is the unit digit in the multiplication of 1×3×5×7×9××9991 \times 3 \times 5 \times 7 \times 9 \times \dots \times 999?

Explanation

All the numbers in the given expression are odd: 1×3×5×7×9××9991 \times 3 \times 5 \times 7 \times 9 \times \dots \times 999

Among these, every group of five consecutive odd numbers (e.g., 1–9, 11–19, 21–29, …, 991–999) has a product ending with 5. For instance, 1×3×5×7×9=9451 \times 3 \times 5 \times 7 \times 9 = 945 → unit digit = 5.

Similarly, 11×13×15×17×1911 \times 13 \times 15 \times 17 \times 19 also ends with 5, and so does each successive group. Thus, the overall multiplication becomes 5×5×5××55 \times 5 \times 5 \times \dots \times 5, which always ends with 5.

Alternatively, multiplying any odd number by 5 always gives a number ending in 5. Since all factors here are odd, the final unit digit of the product must be 55.

Maths PYQs from 2025

Trusted by 2L aspirants

Practice UPSC Prelims PYQs Smarter

Practice Now
  • Track accuracy & weak areas
  • See past trends & repeated themes
Start Practicing Now

PYQs by Papers

Crack UPSC with your
Personal AI Mentor

An AI-powered ecosystem to learn, practice, and evaluate with discipline

SuperKalam
SuperKalam is your personal mentor for UPSC preparation, guiding you at every step of the exam journey.

Download the App

Get it on Google PlayDownload on the App Store
Follow us

ⓒ Snapstack Technologies Private Limited