QUESTION

CSAT

Easy

Maths

Prelims 2025

If 4x84 \leq x \leq 8 and 2y72 \leq y \leq 7, then what is the ratio of the maximum value of (x+y)(x + y) to the minimum value of (xy)(x - y)?

Select an option to attempt

Explanation

Given: 4x84 \le x \le 8 and 2y72 \le y \le 7

To find: Ratio = (maximum value of (x+y)(x + y)) / (minimum value of (xy)(x - y))

Step 1: Maximum of (x+y)(x + y) Occurs when both xx and yy take their maximum values: x=8x = 8, y=7x+y=15y = 7 \rightarrow x + y = 15

Step 2: Minimum of (xy)(x - y) Occurs when xx is minimum and yy is maximum: x=4x = 4, y=7xy=3y = 7 \rightarrow x - y = -3

Step 3: Ratio = (x+y)max(xy)min\frac{(x + y)_{max}}{(x - y)_{min}} = 15(3)=5\frac{15}{(-3)} = -5

Since 5-5 is not among the given options, the correct answer is None of the above (Option D).

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