QUESTION

CSAT

Medium

Maths

Prelims 2025

Consider a set of 11 numbers:

Value-I = Minimum value of the average of the numbers of the set when they are consecutive integers $\ge$ –5. Value-II = Minimum value of the product of the numbers of the set when they are consecutive non-negative integers.

Which one of the following is correct?

Select an option to attempt

Explanation

Total numbers = 11.

For Value-I: We need the smallest possible set of 11 consecutive integers ≥ −5. That set is: −5, −4, −3, −2, −1, 0, 1, 2, 3, 4, 5.

Average = (Sum of numbers) ÷ 11. Since the numbers are symmetrically distributed around 0, Sum = 0 → Average = 0. Hence, Value-I = 0.

For Value-II: We need the minimum product of 11 consecutive non-negative integers. The smallest possible sequence starts at 0: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.

Their product includes 0, so the product = 0. Hence, Value-II = 0.

Therefore, Value-I = Value-II = 0.

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