QUESTION

CSAT

Hard

Reasoning

Prelims 2020

In the particular year 12th January is a Sunday, then which one of the following is correct?

Select an option to attempt

Explanation

We are given that 12th January is a Sunday. We need to determine the correct statement regarding 12th or 15th July in both leap and non-leap years.

Counting the number of odd days from January to July We count the odd days from 12th January to 12th July separately for both leap and non-leap years.

Case 1: If the year is a leap year

  • January (after 12th) → 19 days → (19mod7)=5(19 \mod 7) = 5 odd days
  • February → 29 days → (29mod7)=1(29 \mod 7) = 1 odd day
  • March → 31 days → (31mod7)=3(31 \mod 7) = 3 odd days
  • April → 30 days → (30mod7)=2(30 \mod 7) = 2 odd days
  • May → 31 days → (31mod7)=3(31 \mod 7) = 3 odd days
  • June → 30 days → (30mod7)=2(30 \mod 7) = 2 odd days
  • 12 days of July → (12mod7)=5(12 \mod 7) = 5 odd days Total odd days = 5+1+3+2+3+2+5=215 + 1 + 3 + 2 + 3 + 2 + 5 = 21 odd days → (21mod7)=0(21 \mod 7) = 0 odd days

Since 12th January was Sunday, 12th July is also Sunday in a leap year.

Case 2: If the year is a non-leap year

  • January (after 12th) → 19 days → 5 odd days
  • February → 28 days → 0 odd days
  • March → 31 days → 3 odd days
  • April → 30 days → 2 odd days
  • May → 31 days → 3 odd days
  • June → 30 days → 2 odd days
  • 12 days of July → 5 odd days Total odd days = 5+0+3+2+3+2+5=205 + 0 + 3 + 2 + 3 + 2 + 5 = 20 odd days → (20mod7)=6(20 \mod 7) = 6 odd days

Since 12th January was Sunday, 12th July is Saturday in a non-leap year.

Thus, option C is correct.

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