QUESTION

CSAT

Easy

Reasoning

Prelims 2019

What is X in the sequence 4, 196196, 16, 144144, 36, 100100, 64, X?

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Explanation

The sequence is: 4, 196, 16, 144, 36, 100, 64, X.

Notice that the numbers alternate between small and large values: 4, 16, 36, 64: These are squares of 2, 4, 6, and 8 (i.e., 222^2, 424^2, 626^2, 828^2). 196, 144, 100: These are squares of 14, 12, and 10 (i.e., 14214^2, 12212^2, 10210^2).

The pattern is: The small numbers follow the squares of even numbers: 2, 4, 6, 8. The large numbers follow the squares of even numbers in reverse: 14, 12, 10. For the next large number:

After 14, 12, 10, the next number should be 8. The square of 8 is 64. Thus, X = 64.

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