QUESTION

CSAT

Medium

Reasoning

Prelims 2019

If x is greater than or equal to 25 and y is less than or equal to 40, then which one of the following is always correct?

Select an option to attempt

Explanation

Step 1: Evaluate Option A If $x=25$ and $y=40$ , then x is not greater than y. Therefore, Option A is not always correct.

Step 2: Evaluate Option B If $x=25$ and $y=40$ , then $y-x=40-25=15$ , which is not greater than 15. Therefore, Option B is not always correct.

Step 3: Evaluate Option C If $x=25$ and $y=40$ , then $y-x=40-25=15$ , which is less than or equal to 15. If $x=26$ and $y=39$ , then $y-x=39-26=13$ , which is also less than or equal to 15. Therefore, Option C is always correct.

Step 4: Evaluate Option D If $x=25$ and $y=40$ , then $x+y=25+40=65$ , which satisfies the condition. However, if $x=28$ and $y=30$ , then $x+y=28+30=58$ , which is less than 65. Therefore, Option D is not always correct.