Given: Length of the agricultural field = $X1$ meters Breadth of the agricultural field = $X2$ meters $X1 + X2 = 40$ meters The area A of the rectangular field is given by: $A = X1 \cdot X2$

To find the maximum area: We know that for a rectangle, the area is maximized when the length and breadth are equal. Since $X1 + X2 = 40$, the maximum area will occur when: $X1 = X2 = \frac{40}{2} = 20$ meters

So, the maximum area is: $A = X1 \cdot X2 = 20 \cdot 20 = 400$ sq meters

Therefore, the area will not exceed 400 sq meters.