Question
CSATEasyPrelims 2025Maths

Let P=QQQP = QQQ be a 3-digit number. What is the HCF of PP and 481481?

Explanation

P = QQQ = Q × 111 ⇒ 111=3×37111 = 3 \times 37

So, P = Q × 3 × 37

Also, 481=13×37481 = 13 \times 37

Therefore, both P and 481 share the common factor 37. Since Q (1–9) cannot be 13, no further common factor exists.

Hence, HCF(P, 481) = 37.

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