QUESTION

CSAT

Easy

Maths

Prelims 2023

Consider the following in respect of prime number p and composite number c.

  1. (p+c)(pc)\frac{(p + c)}{(p - c)} can be even.
  2. 2p+c2p + c can be odd.
  3. pcpc can be odd.

Which of the statements given above are correct?

Select an option to attempt

Explanation

Let's place some numbers in place of p and c in the given expressions and check them out.

Statement 1: (p+c)/(pc)=(11+9)/(119)=202=10(p + c)/(p - c) = (11 + 9)/(11 - 9) = \frac{20}{2} = 10 (an even number)

So, statement 1 is correct.

Statement 2: 2p+c=(2×3)+9=152p + c = (2 \times 3) + 9 = 15 (an odd number)

So, statement 2 is correct.

Statement 3: pc=3×9=27pc = 3 \times 9 = 27 (an odd number)

So, statement 3 is correct.

Hence, option D is correct.

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