QUESTION

CSAT

Easy

Reasoning

Prelims 2021

There are three points P, Q and R on a straight line such that PQ:QR=3:5PQ:QR = 3:5. If n is the number of possible values of PQ:PRPQ:PR, then what is n equal to?

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Explanation

We have to arrange three points P, Q, and R on a straight line, such that PQ:QR=3:5PQ : QR = 3 : 5

Three points can be arranged in 3!3!, i.e. 6 ways.

However, the number of possible values of PQ:PRPQ : PR will be only 2, i.e. n=2n = 2.

They have been represented below:

Diagram

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