PQ × 3 = RQQ

Or $(10P + Q) \times 3 = 100R + 10Q + Q$

Or $30P + 3Q = 100R + 11Q$

Or $30P = 100R + 8Q$

The last digit of $30P$ will be 0, as well as that of $100R$. So, the last digit of $8Q$ must also be 0.

So, the value of $Q$ must be 5.

Hence, $30P = 100R + 8Q = 100R + 40$ Or $3P = 10R + 4$

If $R = 1$, then $P = 14/3$ (not an integer) If $R = 2$, then $P = 24/3 = 8$ If $R = 3$, then $P = 34/3$ (not an integer, and in double digits)

So, $P = 8$, $Q = 5$, and $R = 2$ That is, $85 \times 3 = 255$

So, $(P+R)/Q = (8 + 2)/5 = 10/5 = 2$