QUESTION

CSAT

Easy

Maths

Prelims 2019

X, Y, and Z are three contestants in a race of 1000 m. Assume that all run with different uniform speeds. X gives Y a start of 40 m and X gives Z a start of 64 m. If Y and Z were to compete in a race of 1000 m, how many meters start will Y give to Z?

Select an option to attempt

Explanation

X gives Y a start of 4040 m.

It means when X completes 10001000 m, Y will complete 960960 m.

Speed of X : Speed of Y = 1000:9601000 : 960

Speed of X : Speed of Y = 25:2425 : 24 ----------(1)

X gives Z a start of 6464 m.

It means when X completes 10001000 m, Z will complete 936936 m.

Speed of X : Speed of Z = 1000:9361000 : 936

Speed of X : Speed of Z = 125:117125 : 117 ------------(2)

Combining equations (1) and (2), we get

X : Y : Z = 125:120:117125 : 120 : 117

Speed of Y : Speed of Z = 120:117120 : 117

Speed of Y : Speed of Z = 40:3940 : 39

The speed-distance ratio will be equal for Y and Z.

36

36

Y = 25×3925 \times 39

Y = 975975

So when Y finishes 10001000m, Z will complete 975975 m.

It means Y will give Z a headstart of 2525 m.

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