QUESTION

CSAT

Easy

Reasoning

Prelims 2019

An 8-digit number 4252746B leaves remainder ‘0’ when divided by 3. How many values of B are possible?

Select an option to attempt

Explanation

Understand the divisibility rule for 3: A number is divisible by 3 if the sum of its digits is divisible by 3.

Calculate the sum of the known digits: Add the digits of 4252746: 4+2+5+2+7+4+6=304+2+5+2+7+4+6=30

Determine the required sum for divisibility by 3: For the number to be divisible by 3, the total sum of its digits (including BB) must be a multiple of 3.

Set up the equation: Let BB represent the unknown digit. The total sum of the digits is 30+B30+B. For divisibility by 3, 30+B30+B must be divisible by 3.

Solve for possible values of BB: Since 30 leaves a remainder of 0 when divided by 3, BB must also be a multiple of 3 for 30+B30+B to be divisible by 3. The possible values of BB are 0, 3, 6, and 9.

Conclusion: There are 4 possible values for BB (0, 3, 6, and 9) that make the number 4252746 BB divisible by 3. Therefore, the correct answer is C. 4.

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