The single-digit page (From 1 to 9) = $9$ digit Double digit page (From 10 to 99) = $2 \times 90 = 180$ digit Three digit page (From 100 to 999) = $3 \times 900 = 2700$ digit Total digit used = $9 + 180 + 2700 = 2889$ The remaining digit = $3089 - 2889 = 200$ The number of page with four digits = $\frac{200}{4} = 50$ The required number of total page = $999 + 50 = 1049$

The required result will be $1049$.