Let the time taken by the express train to meet the freight train be $t$ hours.

The freight train travels for $(t + 2)$ hours, since it left 2 hours earlier than the express train. Distance covered by the freight train = Speed × Time = $40 \times (t + 2) = 40(t + 2)$ Distance covered by the express train = Speed × Time = $60 \times t = 60t$ Since both trains meet at the same point, their distances are equal: $40(t + 2) = 60t$ Expand the equation: $40t + 80 = 60t$ Solve for $t$: $80 = 60t - 40t$ $80 = 20t$ $t = 4$ Distance from Delhi to the meeting point (distance covered by the express train): Distance = $60 \times 4 = 240$ km Answer: C. 240 km