Step 1: Arrange the boys The number of ways to arrange 2 boys = $2! = 2$

Step 2: Position the girls Available positions for the girls = 3 (before the first boy, between the boys, after the second boy) Choose 2 positions from 3 = $C(3, 2) = 3$

Step 3: Arrange the girls The number of ways to arrange 2 girls in the chosen positions = $2! = 2$

Step 4: Total number of arrangements Total arrangements = $2! \times C(3, 2) \times 2! = 2 \times 3 \times 2 = 12$

Final Answer: 12