Let the number of flowers be F and the number of bees be B.

Condition 1: If one bee lands on each flower, one bee will be left out: Formula: $B = F + 1$

Condition 2: If two bees land on each flower, one flower will be left out: Formula: $F = (\frac{B}{2}) + 1$ Step-by-step calculation: From Condition 1: $B = F + 1$

Substitute this into Condition 2: $F = (\frac{(F + 1)}{2}) + 1$

Simplify the equation: $F - 1 = \frac{(F + 1)}{2}$ $2 * (F - 1) = F + 1$ $2F - 2 = F + 1$ $2F - F = 3$ $F = 3$

Substitute $F = 3$ into $B = F + 1$: $B = 3 + 1 = 4$

Thus, the number of flowers and bees are 3 and 4 respectively.