Question
CSATEasyPrelims 2016Maths

A person walks 12 km due north, then 15 km due east, after that 19 km due west and then 15 km due south. How far is the from the starting point?

Explanation

Distance north: 12 km Distance east: 15 km Distance west: 19 km Distance south: 15 km Net north-south displacement = 12 km - 15 km = -3 km (3 km south) Net east-west displacement = 15 km - 19 km = -4 km (4 km west)

Distance from the starting point = (3)2+(4)2\sqrt{(-3)^2 + (-4)^2} = 9+16\sqrt{9 + 16} = 25\sqrt{25} = 5 km

58

58

Maths PYQs from 2016

Trusted by 2L aspirants

Practice UPSC Prelims PYQs Smarter

Practice Now
  • Track accuracy & weak areas
  • See past trends & repeated themes
Start Practicing Now

PYQs by Papers

Crack UPSC with your
Personal AI Mentor

An AI-powered ecosystem to learn, practice, and evaluate with discipline

SuperKalam
SuperKalam is your personal mentor for UPSC preparation, guiding you at every step of the exam journey.

Download the App

Get it on Google PlayDownload on the App Store
Follow us

ⓒ Snapstack Technologies Private Limited