QUESTION

CSAT

Easy

Maths

Prelims 2016

A person walks 12 km due north, then 15 km due east, after that 19 km due west and then 15 km due south. How far is the from the starting point?

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Explanation

Distance north: 12 km Distance east: 15 km Distance west: 19 km Distance south: 15 km Net north-south displacement = 12 km - 15 km = -3 km (3 km south) Net east-west displacement = 15 km - 19 km = -4 km (4 km west)

Distance from the starting point = $\sqrt{(-3)^2 + (-4)^2}$ = $\sqrt{9 + 16}$ = $\sqrt{25}$ = 5 km

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