QUESTION

CSAT

Easy

Maths

Prelims 2013

A thief running at 8 km/hr is chased by a policeman whose speed is 10 km/hr. If the thief is 100 meters ahead of the policeman, then the time required for the policeman to catch the thief will be:

Select an option to attempt

Explanation

Speed of policeman = 10 km/hr Speed of thief = 8 km/hr Relative speed = $10 - 8 = 2$ km/hr

Convert relative speed to meters per second: 2 km/hr = $\frac{2 \times 1000}{3600}$ m/s = $\frac{5}{9}$ m/s

Distance between them = 100 meters Time = Distance / Relative speed = $100 / (\frac{5}{9}) = 100 \times (\frac{9}{5}) = 180$ seconds = 3 minutes

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Explanation

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