QUESTION

CSAT

Easy

Maths

Prelims 2013

A person can walk a certain distance and drive back in six hours. He can also walk both ways in 10 hours. How much time will he take to drive both ways?

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Explanation

Let's denote:

  • x as the time taken to walk one way (in hours).
  • y as the time taken to drive one way (in hours).

From the problem, we have the following two equations:

  1. Walking one way and driving back: The total time taken for walking one way and driving back is 6 hours. Therefore: x+y=6x + y = 6
  2. Walking both ways: The total time taken for walking both ways is 10 hours. Therefore: 2x=102x = 10

Now, solve for x in the second equation: x=10/2=5x = 10 / 2 = 5

Substitute x = 5 into the first equation: 5+y=65 + y = 6 Solving for y: y=65=1y = 6 - 5 = 1

Now, to find the time taken to drive both ways, we simply multiply y (the time taken to drive one way) by 2: 2y=21=22y = 2 \cdot 1 = 2

Thus, the time taken to drive both ways is:

2 hours.

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