QUESTION

CSAT

Easy

Reasoning

Prelims 2017

Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C, who in turn gives 3 to B while B gives 6 to D who passes on 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by:

Select an option to attempt

Explanation

Initially, each boy has 10 cards:

A: 10 cards B: 10 cards C: 10 cards D: 10 cards E: 10 cards F: 10 cards

Now, let's follow the exchanges:

F borrows 2 cards from A:

A: 102=810 - 2 = 8 cards F: 10+2=1210 + 2 = 12 cards F gives 5 cards to C:

F: 125=712 - 5 = 7 cards C: 10+5=1510 + 5 = 15 cards C gives 3 cards to B:

C: 153=1215 - 3 = 12 cards B: 10+3=1310 + 3 = 13 cards B gives 6 cards to D:

B: 136=713 - 6 = 7 cards D: 10+6=1610 + 6 = 16 cards D gives 1 card to E:

D: 161=1516 - 1 = 15 cards E: 10+1=1110 + 1 = 11 cards

Now let's check the number of cards possessed by D and E:

D: 15 cards E: 11 cards Total = 15+11=2615 + 11 = 26 cards

Now, let's check the total number of cards for different groups:

A, B, and C:

A: 8 cards B: 7 cards C: 12 cards Total = 8+7+12=278 + 7 + 12 = 27 cards B, C, and F:

B: 7 cards C: 12 cards F: 7 cards Total = 7+12+7=267 + 12 + 7 = 26 cards A, B, and F:

A: 8 cards B: 7 cards F: 7 cards Total = 8+7+7=228 + 7 + 7 = 22 cards A, C, and F:

A: 8 cards C: 12 cards F: 7 cards Total = 8+12+7=278 + 12 + 7 = 27 cards The correct answer is: B. B, C and F

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