Given Data:

• 45% read magazine A
• 55% read magazine B
• 40% read magazine C
• 30% read both magazines A and B
• 15% read both magazines B and C
• 25% read both magazines A and C
• 10% read all three magazines A, B, and C

Using the Inclusion-Exclusion Principle: Formula: $P(A \cup B \cup C) = P(A) + P(B) + P(C) - P(A \cap B) - P(B \cap C) - P(A \cap C) + P(A \cap B \cap C)$

Substituting the given values: $P(A \cup B \cup C) = 45\% + 55\% + 40\% - 30\% - 15\% - 25\% + 10\%$

Calculations: $45\% + 55\% + 40\% = 140\%$ $30\% + 15\% + 25\% = 70\%$ $140\% - 70\% = 70\%$ $70\% + 10\% = 80\%$

Thus, 80% of the population reads at least one magazine.

Conclusion: The percentage of the population that does not read any magazine is: $100\% - 80\% = 20\%$

Correct answer: C. 20%