QUESTION

CSAT

Easy

Maths

Prelims 2015

In a society, friends of the same sex hug while friends of opposite sexes shake hands. A group of friends met at a party, resulting in 24 handshakes. What is the possible number of hugs?

Select an option to attempt

Explanation

Total Handshakes = mfm \cdot f Given: Handshakes = 24 mf=24m \cdot f = 24

Total Hugs = (m(m1))2+(f(f1))2\frac{(m \cdot (m - 1))}{2} + \frac{(f \cdot (f - 1))}{2}

Tested pairs for m and f: For m = 6, f = 4:

  • Handshakes: 64=246 \cdot 4 = 24 (Correct)
  • Hugs among males: (6(61))2=15\frac{(6 \cdot (6 - 1))}{2} = 15
  • Hugs among females: (4(41))2=6\frac{(4 \cdot (4 - 1))}{2} = 6
  • Total Hugs: 15+6=2115 + 6 = 21

Therefore, the possible number of hugs is 21.

Trusted by 2L aspirants

Practice UPSC Prelims PYQs Smarter

Practice Now
  • Track accuracy & weak areas
  • See past trends & repeated themes
Start Practicing Now

Crack UPSC with your
Personal AI Mentor

An AI-powered ecosystem to learn, practice, and evaluate with discipline

SuperKalam is your personal mentor for UPSC preparation, guiding you at every step of the exam journey.

Download the App

Get it on Google PlayDownload on the App Store
Follow us

ⓒ Snapstack Technologies Private Limited