QUESTION

CSAT

Easy

Reasoning

Prelims 2015

If ABC × DEED = ABCABC; where A, B, C, D and E are different digits, what are the values of D and E?

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Explanation

The given equation is:

ABC×DEED=ABCABCABC \times DEED = ABCABC

We are told that ABCABC can be written as ABC×1001ABC \times 1001, where ABC is a 3-digit number, and DEED represents a 4-digit number.

The hint given is that ABCABC is divisible by 1001, as 1001 is the product of 13, 11, and 7. So, we can rewrite the equation as:

ABC×1001=ABCABCABC \times 1001 = ABCABC

Now, we know that the number ABCABC is essentially the number ABC repeated twice. Let’s analyze the multiplication:

ABC×1001=ABCABCABC \times 1001 = ABCABC

Since 1001=DEED1001 = DEED, we have:

DEED=1001DEED = 1001

The number 1001 is written as DEED, so D=1D = 1 and E=0E = 0.

Thus, the correct values are:

D=1D = 1, E=0E = 0

So, the correct answer is C. D=1D = 1, E=0E = 0.

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