QUESTION

CSAT

Medium

Reasoning

Prelims 2014

Four persons, Alok, Bhupesh, Chander and Dinesh have a total of Rs. 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact Rs. 5 more than Dinesh has. Who has the maximum amount of money?

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Explanation

Given:

Total money = Rs. 100. Alok + Bhupesh = Chander + Dinesh. Alok has Rs. 5 more than Dinesh. Chander has half the money of Dinesh.

We assign variables: A = Alok's money, B = Bhupesh's money, C = Chander's money, D = Dinesh's money. From the relations:

C=D2C = \frac{D}{2}, A=D+5A = D + 5, and A+B=C+DA + B = C + D. Solving the equations, we find:

D=33.33D = 33.33, A=38.33A = 38.33, C=16.67C = 16.67, B=6.67B = 6.67. Thus, Alok has the maximum amount of money: Rs. 38.33.

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