Given positions:

1. F is 1 km west of D → F $(-1, y)$, D $(0, y)$
2. B is 1 km east of E → E $(x, y)$, B $(x+1, y)$
3. A is 2 km north of E → A $(x, y+2)$
4. C is 1 km east of A → C $(x+1, y+2)$
5. D is 1 km south of A → D $(x, y+1)$

Arranging positions:

• A $(x, y+2)$
• D $(x, y+1)$
• E $(x, y)$

Since A, D, and E lie on the same vertical line, they are collinear.

Answer: Option B (A, D, E)