QUESTION

CSAT

Easy

Maths

Prelims 2013

Out of 120 applications for a post, 70 are male, and 80 have a driver’s license.

What is the ratio between the minimum to maximum number of males having a driver’s license?

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Explanation

Let's denote the following:

  • Total number of applicants: 120120
  • Number of males: 7070
  • Number of applicants with a driver's license: 8080
  • Number of females: 12070=50120 - 70 = 50
  • Number of females with a driver's license: 8080 - (number of males with a driver's license)

Now, we need to find the ratio of the minimum to maximum number of males who have a driver's license.

Maximum number of males with a driver's license: For the maximum number of males with a driver's license, we assume that all the females do not have a driver's license. So, all 80 applicants with a driver's license must be male. Therefore, the maximum number of males with a driver's license is 70 (since there are only 70 males).

Minimum number of males with a driver's license: For the minimum number of males with a driver's license, we assume that as many females as possible have a driver's license. Since there are 50 females, the maximum number of females with a driver's license is 50. Therefore, the remaining number of applicants with a driver's license must be male, which is:

8050=3080 - 50 = 30.

Ratio of the minimum to maximum number of males with a driver's license: The minimum number of males with a driver's license is 30, and the maximum number is 70. The ratio is:

30/70=3/730 / 70 = 3 / 7.

Thus, the ratio between the minimum to maximum number of males having a driver's license is:

3 to 7.

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