Passage

A tennis coach is trying to put together a team of four players for the forthcoming tournament. For this, 7 players are available: males A, B, and C; and females W, X, Y, and Z. All players have equal capability and at least 2 males will be in the team. For a team of four, all players must be able to play with each other. However: B cannot play with W, C cannot play with Z, and W cannot play with Y.
QUESTION

CSAT

Medium

Reasoning

Prelims 2013

If Y is selected and B is rejected, the team will consist of which one of the following groups?

Select an option to attempt

Explanation

Given the constraints:

At least 2 males must be in the team. B cannot play with W. C cannot play with Z. W cannot play with Y. Y is selected, and B is rejected.

Step 1: Analyze the constraint that Y is selected and B is rejected. Y is included in the team, so we need to select 3 more players. B is excluded from the team, so B's pairing with others does not matter.

Step 2: Consider the combinations of male and female players: Since at least 2 males are needed, and B is rejected, the remaining males available are A and C. Y is already included, and there are 2 females left to choose from: W and Z.

Step 3: Analyze the pairing restrictions: B cannot play with W — Since B is excluded, this restriction does not affect us. C cannot play with Z — This means if C is selected, Z cannot be on the team. W cannot play with Y — Since Y is selected, W cannot be on the team.

Step 4: Eliminate invalid options based on restrictions: Option A (A, C, W, Y): W cannot play with Y, so this option is invalid. Option B (A, C, X, Y): There are no restrictions between these players. So, this is a valid combination. Option C (A, C, Y, Z): C cannot play with Z, so this option is invalid. Option D (A, W, Y, Z): W cannot play with Y, so this option is invalid. Conclusion: The only valid option is Option B: A, C, X, and Y.

Correct Answer: B. A, C, X, and Y.

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