To find the largest and smallest possible values for the expression (x×y)+z, we must choose distinct values for x, y, and z from the given set {2,3,4,5}.
Step 1: Finding the largest possible value (M)
To maximize the value of (x×y)+z, we should maximize the product (x×y) because multiplication of numbers greater than 1 yields a larger result than addition.
- The two largest numbers available are 4 and 5. Therefore, we assign x=4 and y=5 (or vice versa), giving a product of 4×5=20.
- The remaining numbers are 2 and 3. To maximize the overall sum, we assign the largest remaining number to z, which is 3.
- Calculating the maximum value:
M=(4×5)+3=20+3=23
Step 2: Finding the smallest possible value (N)
To minimize the value of (x×y)+z, we should minimize the product (x×y).
- The two smallest numbers available are 2 and 3. Therefore, we assign x=2 and y=3 (or vice versa), giving a product of 2×3=6.
- The remaining numbers are 4 and 5. To minimize the overall sum, we assign the smallest remaining number to z, which is 4.
- Calculating the minimum value:
N=(2×3)+4=6+4=10
(Self-check: If we tried x=2,y=4,z=3, the result would be (2×4)+3=11, which is larger than 10. Thus, 10 is indeed the absolute minimum.)
Step 3: Finding the difference (M−N)
Now, we subtract the smallest value from the largest value:
M−N=23−10=13
Therefore, the difference between the largest and smallest possible values is 13.