QUESTION

CSAT

Hard

Maths

Prelims 2024

Let p, q, r and s be distinct positive integers. Let p, q be odd and r, s be even. Consider the following statements:

  1. (pr)2qs(p-r)^{2^{qs}} is even.
  2. (qs)q2s(q-s)^{q^{2s}} is even.
  3. (q+r)2p+s(q + r)^{2^{p + s}} is odd.

Which of the statements given above are correct?

Select an option to attempt

Explanation

We are given that:

  • pp, qq are odd.
  • rr, ss are even.

Let's evaluate each statement:

Statement 1: (pr)2(qs)(p - r)^2 (q * s) is even.

  • Since pp is odd and rr is even, (pr)(p - r) is odd. Squaring an odd number gives an odd result.
  • qq is odd and ss is even, so qsq * s is even.
  • An odd number times an even number is even, so this statement is true.

Statement 2: (qs)q2s(q - s) * q^2 * s is even.

  • qq is odd and ss is even, so qsq - s is odd.
  • q2q^2 is odd (since odd * odd = odd), and ss is even.
  • An odd number multiplied by an odd number and then by an even number is even, so this statement is true.

Statement 3: (q+r)2(p+s)(q + r)^2 (p + s) is odd.

  • qq is odd and rr is even, so (q+r)(q + r) is odd (odd + even = odd).
  • pp is odd and ss is even, so (p+s)(p + s) is odd (odd + even = odd).
  • An odd number squared gives an odd result, and multiplying two odd numbers gives an odd result. Therefore, this statement is true.

Since all three statements are correct, the answer is:

Answer: D. 1, 2 and 3

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