QUESTION

CSAT

Easy

Reasoning

Prelims 2024

In the expression 543215 * 4* 3* 2* 1, * is chosen from ++, -, ×\times each at most two times. What is the smallest non-negative value of the expression?

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Explanation

The first step is to maximize the use of subtraction and addition to reduce the expression to its smallest value.

Approach:

Maximizing Subtraction: Using subtraction will reduce the value of the expression. To achieve the smallest result, we want to subtract as much as possible.

Addition Strategy: Adding numbers whenever required to keep the resulting value non-negative.

Calculation: First, subtract strategically to bring the result to zero: 54=15 - 4 = 1, 13=21 - 3 = -2, 2+2=0-2 + 2 = 0, 0×1=00 \times 1 = 0. By using subtraction, addition and multiplication in the correct order, we achieve a result of 0.

Thus, the smallest non-negative value of the expression is 0.

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