Statement-I: $m + n > mn$ and $m > n$

• For $m = 2$, $n = 1$: $2 + 1 = 3 > 2 \times 1 = 2$, and $2 > 1$, which satisfies both conditions.
• For $m = 3$, $n = 1$: $3 + 1 = 4 > 3 \times 1 = 3$, and $3 > 1$, which satisfies both conditions. This gives multiple possible pairs for $m$ and $n$, so it is not sufficient to uniquely determine $m$ and $n$.

Statement-II: $mn = 24$

Possible pairs are:

• $1 \times 24 = 24$
• $2 \times 12 = 24$
• $3 \times 8 = 24$
• $4 \times 6 = 24$

This also gives multiple possible pairs, so it is not sufficient alone.

Combining Statement-I and Statement-II: From Statement-II, $m$ and $n$ must be pairs where the product is 24. Using Statement-I, we check:

• $(24, 1)$: $24 + 1 = 25 > 24$, also 24 is greater than 1, so this pair statisfy all the conditions.
• Other pairs like $(2, 12)$, $(3, 8)$, and $(4, 6)$ fail to meet the condition $m + n > mn$.

Hence, both statements together provide the unique solution $(m, n) = (24, 1)$.

Conclusion: The question can be answered by using both statements together, but not either statement alone.