QUESTION

CSAT

Hard

Maths

Prelims 2024

A Question is given followed by two Statements I and II. Consider the Question and the Statements. A certain amount was distributed among X, Y and Z. Question: Who received the least amount?

Statement-I: X received 45\frac{4}{5} of what Y and Z together received. Statement-II: Y received 27\frac{2}{7} of what X and Z together received.

Which one of the following is correct in respect of the above Question and the Statements?

Select an option to attempt

Explanation

Using Statement-I alone: From Statement-I, we have X = (4/5)×(Y+Z)(4/5) \times (Y + Z), or X = 4k4k and (Y+Z)=5k(Y + Z) = 5k. This gives us the relationship between X, Y, and Z but does not allow us to determine who received the least. Thus, Statement-I alone is insufficient.

Using Statement-II alone: From Statement-II, we have Y = (2/7)×(X+Z)(2/7) \times (X + Z), or Y = 2k2k and (X+Z)=7k(X + Z) = 7k. This gives us the relationship between Y, X, and Z but does not directly provide the least amount. Hence, Statement-II alone is insufficient.

Combining Statement-I and Statement-II: From both equations:

  • From Statement-I: X = 4k4k and (Y+Z)=5k(Y + Z) = 5k
  • From Statement-II: Y = 2k2k and (X+Z)=7k(X + Z) = 7k

Solving these gives:

  • Y+Z=5kY + Z = 5k
  • 2k+Z=5k2k + Z = 5k, so Z=3kZ = 3k

Now we know X = 4k4k, Y = 2k2k, and Z = 3k3k. Hence, X : Y : Z = 4:2:34 : 2 : 3. Clearly, Y received the least amount.

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