tt0 is a 3-digit number ending with zero, such that pp+qq+rr=tt0
As pp, qq, and rr are 2-digit numbers, the value of tt0 can be either 110 or 220.
If tt0=110
pp+qq+rr=110
or (10p+p)+(10q+q)+(10r+r)=110
or 11p+11q+11r=110
or p+q+r=10 ....... (1)
If tt0=220
pp+qq+rr=220
or (10p+p)+(10q+q)+(10r+r)=220
or 11p+11q+11r=220
or p+q+r=20
Statement 1:
As p<q<r, the possible value of p in equation (1) can be 1 and 2.
As p<q<r, the possible value of p in equation (2) can be 1, 2, 3, 4 and 5.
Hence, the number of possible values of p is 5.
Thus, Statement 1 is correct.
Statement 2:
As p<q<r, the possible value of q in equation (1) can be 2, 3 and 4.
As p<q<r, the possible value of q in equation (2) can be 6, 7 and 8.
Hence, the number of possible values of q is 6.
Thus, Statement 2 is correct.
Hence, option (C) is correct.