QUESTION

CSAT

Easy

Reasoning

Prelims 2022

What is the value of X in the sequence 2, 12, 36, 80, 150, XX?

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Explanation

To find the value of X in the sequence 2, 12, 36, 80, 150, X, let's break down each number in the sequence:

First term: 1×1×2=21 \times 1 \times 2 = 2 Second term: 2×2×3=122 \times 2 \times 3 = 12 Third term: 3×3×4=363 \times 3 \times 4 = 36 Fourth term: 4×4×5=804 \times 4 \times 5 = 80 Fifth term: 5×5×6=1505 \times 5 \times 6 = 150

The pattern is clear: each term in the sequence is the product of three consecutive integers. Therefore, to find the next term, we apply the same pattern:

Sixth term: 6×6×7=2526 \times 6 \times 7 = 252

Thus, the value of X is 252.

Hence, the correct answer is 252.

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