Question
CSATEasyPrelims 2022Reasoning

What is the value of X in the sequence 2, 12, 36, 80, 150, XX?

Explanation

To find the value of X in the sequence 2, 12, 36, 80, 150, X, let's break down each number in the sequence:

First term: 1×1×2=21 \times 1 \times 2 = 2 Second term: 2×2×3=122 \times 2 \times 3 = 12 Third term: 3×3×4=363 \times 3 \times 4 = 36 Fourth term: 4×4×5=804 \times 4 \times 5 = 80 Fifth term: 5×5×6=1505 \times 5 \times 6 = 150

The pattern is clear: each term in the sequence is the product of three consecutive integers. Therefore, to find the next term, we apply the same pattern:

Sixth term: 6×6×7=2526 \times 6 \times 7 = 252

Thus, the value of X is 252.

Hence, the correct answer is 252.

Reasoning PYQs from 2022

Trusted by 2L aspirants

Practice UPSC Prelims PYQs Smarter

Practice Now
  • Track accuracy & weak areas
  • See past trends & repeated themes
Start Practicing Now

PYQs by Papers

Crack UPSC with your
Personal AI Mentor

An AI-powered ecosystem to learn, practice, and evaluate with discipline

SuperKalam
SuperKalam is your personal mentor for UPSC preparation, guiding you at every step of the exam journey.

Download the App

Get it on Google PlayDownload on the App Store
Follow us

ⓒ Snapstack Technologies Private Limited