QUESTION

CSAT

Medium

Maths

Prelims 2022

Let p be a two-digit number and q be the number consisting of same digits written in reverse order. If p×q=2430p \times q = 2430, then what is the difference between p and q?

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Explanation

The given product is p×q=2430p \times q = 2430.

Let the two-digit number pp be represented as: p=10x+5p = 10x + 5 where xx is the tens digit. The number qq, which is the reverse of pp, is: q=50+xq = 50 + x

Substitute these expressions into the equation: (10x+5)(50+x)=2430(10x + 5) * (50 + x) = 2430

Step 1: Expand and simplify Expanding the equation: (10x+5)(50+x)=10x×50+10x×x+5×50+5×x(10x + 5)(50 + x) = 10x \times 50 + 10x \times x + 5 \times 50 + 5 \times x =500x+10x2+250+5x= 500x + 10x^2 + 250 + 5x =10x2+505x+250= 10x^2 + 505x + 250

Thus, the equation becomes: 10x2+505x+250=243010x^2 + 505x + 250 = 2430 Simplify it: 10x2+505x2180=010x^2 + 505x - 2180 = 0

Step 2: Trial and error for possible values of xx Now, let's check values for xx.

Trying x=4x = 4: p=10(4)+5=45p = 10(4) + 5 = 45 q=50+4=54q = 50 + 4 = 54 Check the product: 4554=243045 * 54 = 2430 This is correct.

Step 3: Find the difference Now, the difference between pp and qq is: qp=5445=9q - p = 54 - 45 = 9

Thus, the required difference is 9.

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