QUESTION

CSAT

Medium

Maths

Prelims 2020

What is the least four-digit number when divided by 3, 4, 5 and 6 leaves a remainder 2 in each case?

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Explanation

The L.C.M. of 3, 4, 5, and 6 is 60. Let the required number be 60x+260x+2.

x=17x=17, then the number is:

60×17+2=1020+2=102260 \times 17 + 2 = 1020 + 2 = 1022

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