This is a question involving arithmetic progression. Let the total number of pages in the book be $n$.

The sum of consecutive numbers from 1 to $n$ is given by the formula: Sum= $\frac{2n(n+1)}{2}$ ​This sum is approximately 195. Thus, we have: $n(n+1) \approx 390$ Since a page with two numbers was torn, the actual value of $n(n+1)$ must be greater than 390. The smallest possible value of $n(n+1)$ greater than 390, where $n$ is an integer, occurs when $n=20$.

Therefore, $n(n+1)=20 \times 21=420$ The sum of the first 20 pages is: $\frac{20 \times 21}{2} =210$ The sum of the two numbers on the torn page is: $210-195=15$ Only option B gives the sum of 15, i.e., $7+8=15$.

Hence, option B is the correct answer.