Question
CSATMediumPrelims 2020Maths

For what value of n, the sum of digits in the number (10n+1)(10^n+ 1) is 2?

Explanation

nN = 10ⁿ + 1Sum of Digits of N
0100+1=210^0 + 1 = 22
1101+1=1110^1 + 1 = 111+1=21 + 1 = 2
2102+1=10110^2 + 1 = 1011+0+1=21 + 0 + 1 = 2
3103+1=100110^3 + 1 = 10011+0+0+1=21 + 0 + 0 + 1 = 2

Observation: The sum of digits of N = 10n+110ⁿ + 1 is always 2 for any whole number n.

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