QUESTION

CSAT

Hard

Maths

Prelims 2020

A sum of Rs. 2,500 is distributed among X, Y and Z in two ratio 1/2 ⁣:3/4 ⁣:5/61/2 \colon 3/4 \colon 5/6. What is the difference between the maximum share and the minimum share?

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Explanation

The given ratio of the amounts distributed among X, Y, and Z is:

Step 1: Simplify the Ratio Finding the LCM of denominators (2,4,6)=12(2, 4, 6) = 12. Multiply each term by 12: 6:9:106:9:10

Step 2: Assign Shares Let the shares of X, Y, and Z be 6n6n, 9n9n, and 10n10n, respectively.

Step 3: Use the Given Total Amount 6n+9n+10n=25006n+9n+10n=2500

Simplify: 25n=250025n=2500 n=100n=100

Step 4: Find the Difference Maximum share = 10n=10×100=100010n = 10 \times 100 = 1000 Minimum share = 6n=6×100=6006n = 6 \times 100 = 600

Difference: 1000600=4001000-600=400

Final Answer: The difference between the maximum and minimum shares is Rs. 400.

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