QUESTION

CSAT

Hard

Maths

Prelims 2018

A shopkeeper sells an article at Rs. 40 and gets $X\%$ profit. However, when he sells it at Rs. 20, he faces same percentage of loss. What is the original cost of the article?

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Explanation

let us assume cost price of artistic is $C$ . $C \times \frac{(100 + X)}{100} = 40$ $100C + XC = 4000$ - first equation $C \times \frac{(100 - X)}{100} = 20$ $100C - XC = 2000$ - second equation $100C - 2000 = 4000 - 100C$ $C = 30$

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