QUESTION

CSAT

Hard

Maths

Prelims 2016

30 g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar was mixed in 280 ml of water in vessel B and 20 g of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is

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Explanation

To determine the sweetness of the solutions, we need to calculate the concentration of sugar in each vessel. The concentration of sugar is given by the formula:

Concentration = Amount of water (ml)/Amount of sugar (g) Now, let's calculate the concentration of sugar for each vessel:

Vessel A: Sugar = $30$ g Water = $180$ ml Concentration = $30 / 180 = 0.1667$ g/ml

Vessel B: Sugar = $40$ g Water = $280$ ml Concentration = $40 / 280 = 0.1429$ g/ml

Vessel C: Sugar = $20$ g Water = $100$ ml Concentration = $20 / 100 = 0.2$ g/ml Comparison:

The concentration of sugar in Vessel B is $0.1429$ g/ml. The concentration of sugar in Vessel C is $0.2$ g/ml. Since $0.1429$ g/ml is less than $0.2$ g/ml, the solution in Vessel B is less sweet than that in Vessel C.